What is the derivative of f(x)=3x^2-2x-1 ?

The derivative of f(x)=3x^2-2x-1 is 6x-2

What is the first derivative of f(x)=3x^2-2x-1 ?

The first derivative of f(x)=3x^2-2x-1 is 6x-2

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derivative of

f (x) = 3 x^{2} - 2 x - 1

6 x - 2

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 6 x - 2 - 0

Simplify

= 6 x - 2

\frac{d}{d a} (3 sin^{2} (a) - 2 cos^{2} (a))

\frac{500}{q}

(1 + x^{2})^{\frac{1}{2}}

\frac{d}{d x} (sin (\frac{x}{( y + 1 )}))

\frac{( x + 2 )}{( y - 2 )}

What is the derivative of f(x)=3x^2-2x-1 ?
The derivative of f(x)=3x^2-2x-1 is 6x-2
What is the first derivative of f(x)=3x^2-2x-1 ?
The first derivative of f(x)=3x^2-2x-1 is 6x-2