derivative of-x^3+9x^2-6x+9

Lösung

\frac{d}{d x} (- x^{3} + 9 x^{2} - 6 x + 9)

- 3 x^{2} + 18 x - 6

Schritte zur Lösung

\frac{d}{d x} (- x^{3} + 9 x^{2} - 6 x + 9)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (9 x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (9) = 0

= - 3 x^{2} + 18 x - 6 + 0

Vereinfache

= - 3 x^{2} + 18 x - 6

d er i v a t i v e \frac{8}{64 + 64 t ^{2}}

\frac{d y}{d x} = 2 cos (x) (y + 1), y (\frac{π}{6}) = 2

\frac{\partial}{\partial x} (2 x^{2} y^{2})

n = 0 \sum \infty 9 (\frac{3}{4})^{n}

\int - 2 y d y