What is (\partial)/(\partial x)(2x^2y^2) ?

The answer to (\partial)/(\partial x)(2x^2y^2) is 4xy^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^2y^2)

\frac{\partial}{\partial x} (2 x^{2} y^{2})

4 x y^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y^{2} \cdot 2 x^{2 - 1}

Simplify

= 4 x y^{2}

n = 0 \sum \infty 9 (\frac{3}{4})^{n}

y = x, 0, 4

x \to \infty lim (4 x)

x \to 0 lim (\frac{( e ^{x} - e ^{- x} - 2 sin ( x ) )}{3 x ^{3}})

n = 1 \sum \infty \frac{1}{n}

What is (\partial)/(\partial x)(2x^2y^2) ?
The answer to (\partial)/(\partial x)(2x^2y^2) is 4xy^2