What is the integral of ycos(2y) ?

The integral of ycos(2y) is 1/4 (2ysin(2y)+cos(2y))+C

integral of ycos(2y)

\int y cos (2 y) d y

\frac{1}{4} (2 y sin (2 y) + cos (2 y)) + C

Solution steps

\int y cos (2 y) d y

Apply u-substitution

= \int \frac{u cos ( u )}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int u cos (u) d u

Apply Integration By Parts

= \frac{1}{4} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= \frac{1}{4} (u sin (u) - (- cos (u)))

Substitute back

u = 2 y

= \frac{1}{4} (2 y sin (2 y) - (- cos (2 y)))

Simplify

= \frac{1}{4} (2 y sin (2 y) + cos (2 y))

Add a constant to the solution

= \frac{1}{4} (2 y sin (2 y) + cos (2 y)) + C

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What is the integral of ycos(2y) ?
The integral of ycos(2y) is 1/4 (2ysin(2y)+cos(2y))+C