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Popular Calculus >

y^'=4-y

Solution

y^{^{'}} = 4 - y

Solution

y = - e^{- t - c_{1}} + 4

Solution steps

y^{'} (t) = 4 - y

Solve separable ODE:

y = - e^{- t - c_{1}} + 4

y = - e^{- t - c_{1}} + 4

Graph

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x \to 0 lim (x^{2} cos (\frac{9}{x}))

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\int \frac{2 x}{9 x ^{2} - 12 x + 8} d x

tangent of y=x+sqrt(x),(9,12)

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derivative of-8e^{-x/(10}-40)

\frac{d}{d x} (- 8 e^{- \frac{x}{10}} - 40)

Frequently Asked Questions (FAQ)

What is the solution for y^'=4-y ?
The solution for y^'=4-y is y=-e^{-t-c_{1}}+4