What is the tangent of y=x+sqrt(x),(9,12) ?

The tangent of y=x+sqrt(x),(9,12) is y= 7/6 x+3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=x+sqrt(x),(9,12)

tangent of

y = x + x, (9, 12)

y = \frac{7}{6} x + \frac{3}{2}

Solution steps

Find the slope of

y = x + x : \frac{d y}{d x} = 1 + \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{6}

Find the line with slope m=

\frac{7}{6}

and passing through

(9, 12) : y = \frac{7}{6} x + \frac{3}{2}

y = \frac{7}{6} x + \frac{3}{2}

\frac{d}{d x} (- 8 e^{- \frac{x}{10}} - 40)

\int_{0}^{8} \frac{4}{( x - 6 ) ^{3}} d x

\int 5 x e^{4 x} d x

\int (3 x - 4) \cdot e^{- x} d x

\int sin (\frac{( nπ x )}{2}) d x

What is the tangent of y=x+sqrt(x),(9,12) ?
The tangent of y=x+sqrt(x),(9,12) is y= 7/6 x+3/2