What is the derivative of sin(x^{2x}) ?

The derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)

What is the first derivative of sin(x^{2x}) ?

The first derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)

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\frac{d}{d x} (sin (x^{2 x}))

cos (x^{2 x}) \cdot 2 x^{2 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (sin (x^{2 x}))

Apply the chain rule:

cos (x^{2 x}) \frac{d}{d x} (x^{2 x})

= cos (x^{2 x}) \frac{d}{d x} (x^{2 x})

\frac{d}{d x} (x^{2 x}) = 2 x^{2 x} (ln (x) + 1)

= cos (x^{2 x}) \cdot 2 x^{2 x} (ln (x) + 1)

\frac{d}{d x} ((x + 5)^{3})

y^{^{'}} - 4 y = 3 e^{5 t}

\frac{\partial}{\partial x} (3 y^{2} sin (6 x))

x y^{^{'}} - 3 y^{^{'}} - (x - 3) sin (x) + y = 0

f^{^{'}} (x) = 12 x^{2} - 6 x + 1, f (1) = 5

What is the derivative of sin(x^{2x}) ?
The derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)
What is the first derivative of sin(x^{2x}) ?
The first derivative of sin(x^{2x}) is cos(x^{2x})*2x^{2x}(ln(x)+1)