What is the derivative of 1/(8y^2) ?

The derivative of 1/(8y^2) is -1/(4y^3)

What is the first derivative of 1/(8y^2) ?

The first derivative of 1/(8y^2) is -1/(4y^3)

derivative of

\frac{1}{8 y ^{2}}

- \frac{1}{4 y ^{3}}

Solution steps

\frac{d}{d y} (\frac{1}{8 y ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d y} (\frac{1}{y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{8} \frac{d}{d y} (y^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} (- 2 y^{- 2 - 1})

Simplify

\frac{1}{8} (- 2 y^{- 2 - 1}) : - \frac{1}{4 y ^{3}}

= - \frac{1}{4 y ^{3}}

d er i v a t i v e cos (2 x^{11})

\frac{d}{d x} ((\frac{x}{x + 1})^{2})

d er i v a t i v e e^{- 6 x}

\frac{d}{d x} (7 cos (x) + 3 e^{x})

d er i v a t i v e y = 1 + cot^{2} (x)

What is the derivative of 1/(8y^2) ?
The derivative of 1/(8y^2) is -1/(4y^3)
What is the first derivative of 1/(8y^2) ?
The first derivative of 1/(8y^2) is -1/(4y^3)