What is the derivative of 7cos(x+3e^x) ?

The derivative of 7cos(x+3e^x) is -7sin(x)+3e^x

What is the first derivative of 7cos(x+3e^x) ?

The first derivative of 7cos(x+3e^x) is -7sin(x)+3e^x

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\frac{d}{d x} (7 cos (x) + 3 e^{x})

- 7 sin (x) + 3 e^{x}

Solution steps

\frac{d}{d x} (7 cos (x) + 3 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 cos (x)) + \frac{d}{d x} (3 e^{x})

\frac{d}{d x} (7 cos (x)) = - 7 sin (x)

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= - 7 sin (x) + 3 e^{x}

d er i v a t i v e y = 1 + cot^{2} (x)

\frac{d}{d x} (e^{2 x} + e^{3 x})

y^{^{'}} - 5 y = 10

\frac{d}{d x} (x^{9} ln (x))

\frac{d y}{d x} = - \frac{3 x}{y}

What is the derivative of 7cos(x+3e^x) ?
The derivative of 7cos(x+3e^x) is -7sin(x)+3e^x
What is the first derivative of 7cos(x+3e^x) ?
The first derivative of 7cos(x+3e^x) is -7sin(x)+3e^x