What is area-x^2+10x-16,2x-4,2,8 ?

The answer to area-x^2+10x-16,2x-4,2,8 is 64/3

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area-x^2+10x-16,2x-4,2,8

area

- x^{2} + 10 x - 16, 2 x - 4, 2, 8

\frac{64}{3}

Decimal

21.33333 \dots

Solution steps

Apply the area formula:

\int_{2}^{8} - x^{2} + 10 x - 16 - (2 x - 4) d x

Solve

\int_{2}^{8} - x^{2} + 10 x - 16 - (2 x - 4) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

\frac{d}{d x} (2 arcsin (x - 1))

in v erse l a pl a ce \frac{20}{s ( s ^{2} + 6 s + 144 )}

a re a y = \frac{3}{x}, y = \frac{3}{x ^{2}}, x = 4

d er i v a t i v e f (x) = 800 - 800 x^{- 1}

d er i v a t i v e y = \frac{2 x + 5}{x}

What is area-x^2+10x-16,2x-4,2,8 ?
The answer to area-x^2+10x-16,2x-4,2,8 is 64/3