What is the integral of e^{5x}x ?

The integral of e^{5x}x is 1/25 (e^{5x}*5x-e^{5x})+C

integral of e^{5x}x

\int e^{5 x} x d x

\frac{1}{25} (e^{5 x} \cdot 5 x - e^{5 x}) + C

Solution steps

\int e^{5 x} x d x

Apply u-substitution

= \int \frac{e ^{u} u}{25} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{25} \cdot \int e^{u} u d u

Apply Integration By Parts

= \frac{1}{25} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{25} (e^{u} u - e^{u})

Substitute back

u = 5 x

= \frac{1}{25} (e^{5 x} \cdot 5 x - e^{5 x})

Add a constant to the solution

= \frac{1}{25} (e^{5 x} \cdot 5 x - e^{5 x}) + C

\int \frac{2}{x 9 x ^{2} + 1} d x

\int \frac{x ^{2} + 5 x + 7}{x + 3} d x

in v erse l a pl a ce \frac{4 s e ^{- 3 s}}{( s ^{2} + 4 )}

im pl i c i t \frac{d y}{d x}, y = 2 x - 5

n = 1 \sum \infty arctan (4 n)

What is the integral of e^{5x}x ?
The integral of e^{5x}x is 1/25 (e^{5x}*5x-e^{5x})+C