What is the sum from n=1 to infinity of arctan(4n) ?

The sum from n=1 to infinity of arctan(4n) is diverges

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sum from n=1 to infinity of arctan(4n)

n = 1 \sum \infty arctan (4 n)

diverges

Solution steps

n = 1 \sum \infty arctan (4 n)

Apply Series Divergence Test:

diverges

= diverges

in v erse l a pl a ce \frac{2 s ^{2} + 1}{s + 3}

\frac{x d y}{d x} = y + x e^{- \frac{y}{x}}

\frac{d}{d x} ((ln (x) + 3 x)^{2})

\frac{\partial}{\partial x} (ln (x + 9 y + 2 z))

\frac{d}{d x} (2 tan (x + \frac{π}{12}))

What is the sum from n=1 to infinity of arctan(4n) ?
The sum from n=1 to infinity of arctan(4n) is diverges