What is the integral from 0 to 9 of x^2 ?

The integral from 0 to 9 of x^2 is 243

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 9 of x^2

\int_{0}^{9} x^{2} d x

243

Solution steps

\int_{0}^{9} x^{2} d x

Apply the Power Rule

= [\frac{x ^{3}}{3}]_{0}^{9}

Compute the boundaries:

243

= 243

\frac{\partial}{\partial y} (y^{3} sin (4 x))

\int x csch^{2} (\frac{x ^{2}}{2}) d x

d er i v a t i v e \frac{( x ^{2} - 1 )}{( x ^{2} + x + 1 )}

d er i v a t i v e f (x) = (8 (x^{3} - 6 x^{2} + 12 x))

\frac{\partial}{\partial x} (\frac{cos ( x ^{2} \cdot y )}{z ^{3}})

What is the integral from 0 to 9 of x^2 ?
The integral from 0 to 9 of x^2 is 243