What is the derivative of-9cos(x) ?

The derivative of-9cos(x) is 9sin(x)

What is the first derivative of-9cos(x) ?

The first derivative of-9cos(x) is 9sin(x)

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\frac{d}{d x} (- 9 cos (x))

9 sin (x)

Solution steps

\frac{d}{d x} (- 9 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{d}{d x} (cos (x))

Apply the common derivative:

\frac{d}{d x} (cos (x)) = - sin (x)

= - 9 (- sin (x))

Simplify

= 9 sin (x)

\frac{\partial}{\partial x} (x^{2} + y^{2} + x y)

\int_{- \infty}^{0} e^{6 x} d x

\frac{d}{d x} (ln (5^{x}))

\frac{\partial}{\partial x} (\frac{- 4}{x + y})

d er i v a t i v e y = \frac{1}{7 x ^{\frac{6}{7}}}

What is the derivative of-9cos(x) ?
The derivative of-9cos(x) is 9sin(x)
What is the first derivative of-9cos(x) ?
The first derivative of-9cos(x) is 9sin(x)