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Popular Calculus >

-y^'+(4y)/x =xy^2

Solution

- y^{^{'}} + \frac{4 y}{x} = x y^{2}

Solution

y = \frac{6 x ^{4}}{x ^{6} + c _{1}}

Solution steps

- y^{'} (x) + \frac{4 y}{x} = x y^{2}

Solve Bernoulli ODE:

y = \frac{6 x ^{4}}{x ^{6} + c _{1}}

y = \frac{6 x ^{4}}{x ^{6} + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for -y^'+(4y)/x =xy^2 ?
The solution for -y^'+(4y)/x =xy^2 is y=(6x^4)/(x^6+c_{1)}