integral of-tan(x)+1

Lösung

\int - tan (x) + 1 d x

ln ∣ cos (x) ∣ + x + C

Schritte zur Lösung

\int - tan (x) + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int tan (x) d x + \int 1 d x

\int tan (x) d x = - ln ∣ cos (x) ∣

\int 1 d x = x

= - (- ln ∣ cos (x) ∣) + x

Vereinfache

= ln ∣ cos (x) ∣ + x

Füge eine Konstante zur Lösung hinzu

= ln ∣ cos (x) ∣ + x + C

\int (1 - x) ln (x) d x

\int \frac{sin ( 2 x )}{1 + sin ^{2} ( x )} d x

\frac{\partial}{\partial y} (sin (x^{3} y^{2}))

\frac{\partial}{\partial y} (3 x^{2} y^{4} - 4)

d er i v a t i v e \frac{2}{x ^{2} + 3}