What is the derivative of sin(x^2+2x-1) ?

The derivative of sin(x^2+2x-1) is cos(x^2+2x-1)(2x+2)

What is the first derivative of sin(x^2+2x-1) ?

The first derivative of sin(x^2+2x-1) is cos(x^2+2x-1)(2x+2)

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\frac{d}{d x} (sin (x^{2} + 2 x - 1))

cos (x^{2} + 2 x - 1) (2 x + 2)

Solution steps

\frac{d}{d x} (sin (x^{2} + 2 x - 1))

Apply the chain rule:

cos (x^{2} + 2 x - 1) \frac{d}{d x} (x^{2} + 2 x - 1)

= cos (x^{2} + 2 x - 1) \frac{d}{d x} (x^{2} + 2 x - 1)

\frac{d}{d x} (x^{2} + 2 x - 1) = 2 x + 2

= cos (x^{2} + 2 x - 1) (2 x + 2)

\frac{\partial}{\partial x} (ln (x + y))

d er i v a t i v e \frac{1}{3 + x}

d er i v a t i v e \frac{x}{x ^{2} - 1}

\int 6 e^{3 x} - \frac{8}{e ^{2 x}} d x

y^{^{''}} - 4 y^{^{'}} + 4 y = (x + 1) e^{2 x}

What is the derivative of sin(x^2+2x-1) ?
The derivative of sin(x^2+2x-1) is cos(x^2+2x-1)(2x+2)
What is the first derivative of sin(x^2+2x-1) ?
The first derivative of sin(x^2+2x-1) is cos(x^2+2x-1)(2x+2)