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tangent f(x)=sqrt(x),(-1,1)

解答

切线

f (x) = x, (- 1, 1)

解答

y = \frac{2 - 1}{2} x + 1 + \frac{2 - 1}{2}

求解步骤

(- 1, 1)

处的切线斜率:

m = \frac{x - 1}{x + 1}

计算

f (x) = x

的斜率:

m = \frac{1}{2 x}

解

\frac{1}{2 x} = \frac{x - 1}{x + 1} : x = 3 + 22

求出

x = 3 + 22

处的切线:

y = \frac{2 - 1}{2} x + 1 + \frac{2 - 1}{2}

y = \frac{2 - 1}{2} x + 1 + \frac{2 - 1}{2}

作图

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