implicit (dy)/(dx),3x-tan(y)=4

解答

隐函数求导

\frac{d y}{d x}, 3 x - tan (y) = 4

\frac{d y}{d x} = \frac{3}{sec ^{2} ( y )}

求解步骤

3 x - tan (y) = 4

将

y

视为

y (x)

对两侧微分:

3 - sec^{2} (y) \frac{d y}{d x} = 0

整理

\frac{d y}{d x} : \frac{d y}{d x} = \frac{3}{sec ^{2} ( y )}

\frac{d y}{d x} = \frac{3}{sec ^{2} ( y )}

\int_{3}^{5} \frac{2 t}{t ^{2} - 4 t + 4} d t

d er i v a t i v e 2 e^{x} + \frac{2}{3 x}

y^{^{'}} = \frac{4 x ^{3} + y ^{3}}{x y ^{2}}

\int (x^{2} + x)^{2} d x

n = 0 \sum \infty \frac{1}{2 ( 2 n + 1 )}