What is the solution for y^'=(4x^3+y^3)/(xy^2) ?

The solution for y^'=(4x^3+y^3)/(xy^2) is y=x\sqrt[3]{12ln(x)+c_{1}}

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y^'=(4x^3+y^3)/(xy^2)

y^{^{'}} = \frac{4 x ^{3} + y ^{3}}{x y ^{2}}

y = x 3 12 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{4 x ^{3} + y ^{3}}{x y ^{2}}

Solve Bernoulli ODE:

y = x 3 12 ln (x) + c_{1}

y = x 3 12 ln (x) + c_{1}

\int (x^{2} + x)^{2} d x

n = 0 \sum \infty \frac{1}{2 ( 2 n + 1 )}

x \to 0 lim (\frac{50 x ^{2}}{sin ( x ) + 50 x ^{2}})

\int_{0}^{1} e^{2 x} d x

t an g e n t f (x) = x^{3} - 2 x - 2, at x = - 1

What is the solution for y^'=(4x^3+y^3)/(xy^2) ?
The solution for y^'=(4x^3+y^3)/(xy^2) is y=x\sqrt[3]{12ln(x)+c_{1}}