y^{''}-4y^'+13y=2e^x

Lösung

y^{^{''}} - 4 y^{^{'}} + 13 y = 2 e^{x}

y = e^{2 x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + \frac{1}{5} e^{x}

Schritte zur Lösung

y^{''} (x) - 4 y^{'} (x) + 13 y = 2 e^{x}

Solve linear ODE:

y = e^{2 x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + \frac{1}{5} e^{x}

y = e^{2 x} (c_{1} cos (3 x) + c_{2} sin (3 x)) + \frac{1}{5} e^{x}

\frac{d}{d x} (x^{\frac{3}{2}} lo g_{2} (x + 1))

\int \frac{2}{3} x^{4} d x

\frac{\partial}{\partial x} (e^{y^{2}})

\int x (x + 1)^{100} d x

t an g e n t f (x) = e^{5 x}, at x = \frac{1}{5} ln (5)