What is the limit as x approaches 3+of (x+1)/(x^2-9) ?

The limit as x approaches 3+of (x+1)/(x^2-9) is infinity

limit as x approaches 3+of (x+1)/(x^2-9)

x \to 3 + lim (\frac{x + 1}{x ^{2} - 9})

\infty

Solution steps

x \to 3 + lim (\frac{x + 1}{x ^{2} - 9})

\frac{x + 1}{x ^{2} - 9} = (x + 1) \frac{1}{x ^{2} - 9}

= x \to 3 + lim ((x + 1) \frac{1}{x ^{2} - 9})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 3 + lim (x + 1) \cdot x \to 3 + lim (\frac{1}{x ^{2} - 9})

x \to 3 + lim (x + 1) = 4

x \to 3 + lim (\frac{1}{x ^{2} - 9}) = \infty

= 4 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

\int (8 x - 10 y + 2) d y

y^{^{''}} + 2 y^{^{'}} + 2 y = 0

\frac{\partial}{\partial y} (\frac{x}{x ^{6} - y ^{4}})

y^{^{'}} + y = e^{- t} - 1

\frac{d}{d x} (5 x^{4} ln (x) + x^{4})

What is the limit as x approaches 3+of (x+1)/(x^2-9) ?
The limit as x approaches 3+of (x+1)/(x^2-9) is infinity