f^'(x)=5x^2+7

Lösung

f^{^{'}} (x) = 5 x^{2} + 7

f (x) = \frac{5 x ^{3}}{3} + 7 x + c_{1}

Schritte zur Lösung

f^{'} (x) = 5 x^{2} + 7

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int 5 x^{2} + 7 d x

\int 5 x^{2} + 7 d x = \frac{5 x ^{3}}{3} + 7 x + c_{1}

f (x) = \frac{5 x ^{3}}{3} + 7 x + c_{1}

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