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Popular Calculus >

y-2y^'+y=0

Solution

y - 2 y^{^{'}} + y = 0

Solution

y = e^{t + c_{1}}

Solution steps

y - 2 y^{'} (t) + y = 0

Solve separable ODE:

y = e^{t + c_{1}}

y = e^{t + c_{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y-2y^'+y=0 ?
The solution for y-2y^'+y=0 is y=e^{t+c_{1}}