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Popular Calculus >

area x^2-4,y=0

Solution

area

x^{2} - 4, y = 0

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} - 4 d x

Solve

\int_{- 2}^{2} x^{2} - 4 d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

integral of 64x^2cos(4x)

\int 64 x^{2} cos (4 x) d x

derivative of g(t)= 9/(sqrt(t))

d er i v a t i v e g (t) = \frac{9}{t}

(dy)/(dx)+6x^2y=e^{-2x^3}

\frac{d y}{d x} + 6 x^{2} y = e^{- 2 x^{3}}

derivative of arccsc(2x)

\frac{d}{d x} (arccsc (2 x))

(dy)/(dt)-3y=3e^{4t}

\frac{d y}{d t} - 3 y = 3 e^{4 t}

Frequently Asked Questions (FAQ)

What is area x^2-4,y=0 ?
The answer to area x^2-4,y=0 is 32/3