derivative of arccsc(2x)

解答

\frac{d}{d x} (arccsc (2 x))

- \frac{1}{x 4 x ^{2} - 1}

求解步骤

\frac{d}{d x} (arccsc (2 x))

使用连锁律:

- \frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \frac{d}{d x} (2 x)

= - \frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - \frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \cdot 2

化简

- \frac{1}{( 2 x ) ^{2} ( 2 x ) ^{2} - 1} \cdot 2 : - \frac{1}{x 4 x ^{2} - 1}

= - \frac{1}{x 4 x ^{2} - 1}

\frac{d y}{d t} - 3 y = 3 e^{4 t}

d er i v a t i v e y = 2 x^{2} lo g_{e} (x) - x^{2}

\frac{d y}{d x} = \frac{y}{x} + \frac{( y ^{2} )}{x ^{2}}

\frac{d}{d x} (\frac{3}{4 x - 5})

x y^{^{'}} = y ln (x y)