(y-x4)dx+(x+y4)dy=0

Lösung

(y - x 4) d x + (x + y 4) d y = 0

y = \frac{- x + 17 x ^{2} + c _{1}}{4}, y = \frac{- x - 17 x ^{2} + c _{1}}{4}

Schritte zur Lösung

(y - x 4) d x + (x + y 4) d y = 0

Solve exact ODE:

y = \frac{- x + 17 x ^{2} + c _{1}}{4}, y = \frac{- x - 17 x ^{2} + c _{1}}{4}

y = \frac{- x + 17 x ^{2} + c _{1}}{4}, y = \frac{- x - 17 x ^{2} + c _{1}}{4}

\frac{d y}{d x} = 4 x e^{2 x}

\frac{\partial}{\partial x} (x + ln (5 x + y))

\frac{\partial}{\partial y} (cos (2 x) y)

\int \frac{1}{y ^{4} y ^{2} - 5} d y

d er i v a t i v e ln (k x)