y^'=3-6x+y-2xy

解答

y^{^{'}} = 3 - 6 x + y - 2 x y

y = e^{x - x^{2} + c_{1}} - 3

求解步骤

y^{'} (x) = 3 - 6 x + y - 2 x y

求解可分离方程:

y = e^{x - x^{2} + c_{1}} - 3

y = e^{x - x^{2} + c_{1}} - 3

\int sin (3 x) + cos (5 x) d x

in v erse l a pl a ce \frac{3 s + 3}{s ^{2} - 9}

\frac{\partial}{\partial x} (2 (x + c))

\int 3 t^{3} d t

d er i v a t i v e f (x) = ln (1 + x)