What is the derivative of f(x)=ln(1+x) ?

The derivative of f(x)=ln(1+x) is 1/(1+x)

What is the first derivative of f(x)=ln(1+x) ?

The first derivative of f(x)=ln(1+x) is 1/(1+x)

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derivative of

f (x) = ln (1 + x)

\frac{1}{1 + x}

Solution steps

\frac{d}{d x} (ln (1 + x))

Apply the chain rule:

\frac{1}{1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= \frac{1}{1 + x} \cdot 1

Simplify

= \frac{1}{1 + x}

\int (a x + b)^{n} d x

\frac{d}{d x} (e^{3 x} \cdot cos (2 x))

\int_{0}^{\frac{π}{12}} 6 tan (3 x) d x

x \to 2 lim (2 x^{3} - 3 x^{2} + 4 x - 9)

y^{^{''}} + 2 y^{^{'}} + y = x e^{- x}

What is the derivative of f(x)=ln(1+x) ?
The derivative of f(x)=ln(1+x) is 1/(1+x)
What is the first derivative of f(x)=ln(1+x) ?
The first derivative of f(x)=ln(1+x) is 1/(1+x)