What are the solutions to the equation 176t-16t^2=0 ?

The solutions to the equation 176t-16t^2=0 are t=0,t=11

Find the zeros of 176t-16t^2=0

The zeros of 176t-16t^2=0 are t=0,t=11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

176 t - 16 t^{2} = 0

t = 0, t = 11

Solution steps

176 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 176 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 176 \pm 17 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

17 6^{2} - 4 (- 16) \cdot 0 = 176

t_{1, 2} = \frac{- 176 \pm 176}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 176 + 176}{2 ( - 16 )}, t_{2} = \frac{- 176 - 176}{2 ( - 16 )}

t = \frac{- 176 + 176}{2 ( - 16 )} : 0

t = \frac{- 176 - 176}{2 ( - 16 )} : 11

The solutions to the quadratic equation are:

t = 0, t = 11

\frac{5}{40}

- \frac{15}{3}

lo g_{2} (- 32)

- lo g_{2} (2)

3 x^{2} + 16 x > 6 x + 4

What are the solutions to the equation 176t-16t^2=0 ?
The solutions to the equation 176t-16t^2=0 are t=0,t=11
Find the zeros of 176t-16t^2=0
The zeros of 176t-16t^2=0 are t=0,t=11