2=|r-6|

Lösung

2 = ∣ r - 6 ∣

r = 4 or r = 8

Schritte zur Lösung

2 = ∣ r - 6 ∣

Tausche die Seiten

∣ r - 6 ∣ = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

r - 6 = - 2 or r - 6 = 2

r - 6 = - 2 or r - 6 = 2

r = 4 or r = 8

- \frac{x + 5}{2} \leq \frac{12 + 3 x}{4}

9 x^{2} - 6 x + 5 = 0

\frac{x ^{2} - 2}{1 - 2 x} > 1

\frac{x - 3}{x + 2} < 0

2 c + (3 c - 4) = 5 c - 4