(x-3)/(x+2)<0

Lösung

\frac{x - 3}{x + 2} < 0

- 2 < x < 3

Intervall-Notation

(- 2, 3)

Schritte zur Lösung

\frac{x - 3}{x + 2} < 0

Identifiziere die Intervalle

- 2 < x < 3

2 c + (3 c - 4) = 5 c - 4

(2 x - 6) (2 x - 4) < 0

4 (x + 3) = x

f a c t or x^{2} + 6 x - 16

3 x \leq 2 x + 3