What is (-1)/(x-6)< 2/(9-x) ?

The solution to (-1)/(x-6)< 2/(9-x) is x<3\lor 6<x<9

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(-1)/(x-6)< 2/(9-x)

\frac{- 1}{x - 6} < \frac{2}{9 - x}

x < 3 or 6 < x < 9

Interval Notation

(- \infty, 3) \cup (6, 9)

Solution steps

\frac{- 1}{x - 6} < \frac{2}{9 - x}

Rewrite in standard form

\frac{- x + 3}{( x - 6 ) ( - x + 9 )} < 0

Identify the intervals

x < 3 or 6 < x < 9

(2 + 2)^{2}

16 x^{2} - 12 x + 4 = 0

\frac{x ^{2} - 4}{x ^{2} - 36} \leq 0

\frac{- 3 m}{( 4 m - 7 ) ( 2 m - 5 )} - \frac{8}{( 6 m + 1 ) ( 2 m - 5 )}

5 x - 9 \leq 2 x + 18

What is (-1)/(x-6)< 2/(9-x) ?
The solution to (-1)/(x-6)< 2/(9-x) is x<3\lor 6<x<9