What is (x^2-4)/(x^2-36)<= 0 ?

The solution to (x^2-4)/(x^2-36)<= 0 is -6<x<=-2\lor 2<= x<6

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(x^2-4)/(x^2-36)<= 0

\frac{x ^{2} - 4}{x ^{2} - 36} \leq 0

- 6 < x \leq - 2 or 2 \leq x < 6

Interval Notation

(- 6, - 2] \cup [2, 6)

Solution steps

\frac{x ^{2} - 4}{x ^{2} - 36} \leq 0

Factor

\frac{x ^{2} - 4}{x ^{2} - 36} : \frac{( x + 2 ) ( x - 2 )}{( x + 6 ) ( x - 6 )}

\frac{( x + 2 ) ( x - 2 )}{( x + 6 ) ( x - 6 )} \leq 0

Identify the intervals

- 6 < x \leq - 2 or 2 \leq x < 6

\frac{- 3 m}{( 4 m - 7 ) ( 2 m - 5 )} - \frac{8}{( 6 m + 1 ) ( 2 m - 5 )}

5 x - 9 \leq 2 x + 18

\frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \frac{1}{81}

∣ x + 5 ∣ > 2

x^{4} - 4 x^{3} + 3 x^{2} + 4 x - 4 = (1 - x)^{4} - 3 x^{2} + 2 x - 5

What is (x^2-4)/(x^2-36)<= 0 ?
The solution to (x^2-4)/(x^2-36)<= 0 is -6<x<=-2\lor 2<= x<6