What are the solutions to the equation (x-3)(x-8)=0 ?

The solutions to the equation (x-3)(x-8)=0 are x=3,x=8

Find the zeros of (x-3)(x-8)=0

The zeros of (x-3)(x-8)=0 are x=3,x=8

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(x - 3) (x - 8) = 0

x = 3, x = 8

Solution steps

(x - 3) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 8 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = 3, x = 8

- (3 x - 5) + 2 (x - 8) = - 1

x - 4 = \frac{3}{4} x

\frac{x + 4}{x - 2} \geq 3

\frac{3}{12}

4 (r + 20) = \frac{1}{5} (20 r + 400)

What are the solutions to the equation (x-3)(x-8)=0 ?
The solutions to the equation (x-3)(x-8)=0 are x=3,x=8
Find the zeros of (x-3)(x-8)=0
The zeros of (x-3)(x-8)=0 are x=3,x=8