What is the answer to 4(r+20)= 1/5 (20r+400) ?

The answer to 4(r+20)= 1/5 (20r+400) is True for all r

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4(r+20)= 1/5 (20r+400)

4 (r + 20) = \frac{1}{5} (20 r + 400)

True for all r

Solution steps

4 (r + 20) = \frac{1}{5} (20 r + 400)

Expand

4 (r + 20) : 4 r + 80

Expand

\frac{1}{5} (20 r + 400) : 4 r + 80

4 r + 80 = 4 r + 80

Move

80

to the right side

4 r = 4 r

Move

4 r

to the left side

0 = 0

Both sides are equal

True for all r

\frac{9}{12}

(x + 3) (x + 4) > 0

- 0.8 b^{2} + 7.4 b + (5.6 b - 0.2 b^{2})

\frac{( 0 ^{2} + 1 )}{3}

∣ 2 x ∣ + 4 < 7

What is the answer to 4(r+20)= 1/5 (20r+400) ?
The answer to 4(r+20)= 1/5 (20r+400) is True for all r
Solve for r: 4(r+20)= 1/5 (20r+400)
The solution is True for all r