What are the solutions to the equation 12x^2-220x+600=0 ?

The solutions to the equation 12x^2-220x+600=0 are x=15,x= 10/3

Find the zeros of 12x^2-220x+600=0

The zeros of 12x^2-220x+600=0 are x=15,x= 10/3

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12 x^{2} - 220 x + 600 = 0

x = 15, x = \frac{10}{3}

Decimal Notation

x = 15, x = 3.33333 \dots

Solution steps

12 x^{2} - 220 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 220 ) \pm ( - 220 ) ^{2} - 4 \cdot 12 \cdot 600}{2 \cdot 12}

(- 220)^{2} - 4 \cdot 12 \cdot 600 = 140

x_{1, 2} = \frac{- ( - 220 ) \pm 140}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 220 ) + 140}{2 \cdot 12}, x_{2} = \frac{- ( - 220 ) - 140}{2 \cdot 12}

x = \frac{- ( - 220 ) + 140}{2 \cdot 12} : 15

x = \frac{- ( - 220 ) - 140}{2 \cdot 12} : \frac{10}{3}

The solutions to the quadratic equation are:

x = 15, x = \frac{10}{3}

\frac{4 a ^{2} + 3 a + 2}{a ^{3} - 1} - \frac{1 - 2 a}{a ^{2} + a + 1}

5 x + 11 < 6

\frac{3 x - 4}{2} > \frac{6 - 2 x}{3}

(- 10)^{2}

5 x + \frac{1}{2} - 4 < 8

What are the solutions to the equation 12x^2-220x+600=0 ?
The solutions to the equation 12x^2-220x+600=0 are x=15,x= 10/3
Find the zeros of 12x^2-220x+600=0
The zeros of 12x^2-220x+600=0 are x=15,x= 10/3