What is factor 81x^4-16 ?

The solution to factor 81x^4-16 is (9x^2+4)(3x+2)(3x-2)

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factor 81x^4-16

factor

81 x^{4} - 16

(9 x^{2} + 4) (3 x + 2) (3 x - 2)

Solution steps

81 x^{4} - 16

Apply exponent rules

= (9 x^{2})^{2} - 4^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(9 x^{2})^{2} - 4^{2} = (9 x^{2} + 4) (9 x^{2} - 4)

= (9 x^{2} + 4) (9 x^{2} - 4)

Factor

9 x^{2} - 4 : (3 x + 2) (3 x - 2)

= (9 x^{2} + 4) (3 x + 2) (3 x - 2)

(x + 2)^{2} - (x - 2)^{2}

\frac{60 π}{180}

x^{2} + 16 + 15

5 w^{2} + 20 w = 0

(\frac{4}{5})^{2}

What is factor 81x^4-16 ?
The solution to factor 81x^4-16 is (9x^2+4)(3x+2)(3x-2)