What are the solutions to the equation 17=5-6x-x^2 ?

The solutions to the equation 17=5-6x-x^2 are x=-3-sqrt(3)i,x=-3+sqrt(3)i

Find the zeros of 17=5-6x-x^2

The zeros of 17=5-6x-x^2 are x=-3-sqrt(3)i,x=-3+sqrt(3)i

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17 = 5 - 6 x - x^{2}

x = - 3 - 3 i, x = - 3 + 3 i

Solution steps

17 = 5 - 6 x - x^{2}

Switch sides

5 - 6 x - x^{2} = 17

Move

17

to the left side

- x^{2} - 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) ( - 12 )}{2 ( - 1 )}

Simplify

(- 6)^{2} - 4 (- 1) (- 12) : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 3 i}{2 ( - 1 )} : - 3 - 3 i

x = \frac{- ( - 6 ) - 2 3 i}{2 ( - 1 )} : - 3 + 3 i

The solutions to the quadratic equation are:

x = - 3 - 3 i, x = - 3 + 3 i

- 4 - 3

x \leq - 5 and x \leq - 3

lo g_{2} (x^{2} - 6 x) \leq 3 + lo g_{2} (1 - x)

2 x^{2} + 5 x - 9 = 0

(2^{2})^{\frac{3}{2}}

What are the solutions to the equation 17=5-6x-x^2 ?
The solutions to the equation 17=5-6x-x^2 are x=-3-sqrt(3)i,x=-3+sqrt(3)i
Find the zeros of 17=5-6x-x^2
The zeros of 17=5-6x-x^2 are x=-3-sqrt(3)i,x=-3+sqrt(3)i