What are the solutions to the equation x^2+8x-20=0 ?

The solutions to the equation x^2+8x-20=0 are x=2,x=-10

Find the zeros of x^2+8x-20=0

The zeros of x^2+8x-20=0 are x=2,x=-10

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x^{2} + 8 x - 20 = 0

x = 2, x = - 10

Solution steps

x^{2} + 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 1}, x_{2} = \frac{- 8 - 12}{2 \cdot 1}

x = \frac{- 8 + 12}{2 \cdot 1} : 2

x = \frac{- 8 - 12}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

(\frac{7}{9})^{3}

- x + 2 + 3 x = 5 x - 1

5 x y + 10 x^{2} y

∣ 3 x + 12 ∣ = 0

(3 - i)^{2}

What are the solutions to the equation x^2+8x-20=0 ?
The solutions to the equation x^2+8x-20=0 are x=2,x=-10
Find the zeros of x^2+8x-20=0
The zeros of x^2+8x-20=0 are x=2,x=-10