faktorisieren x^3-2x-1

Lösung

faktorisieren

x^{3} - 2 x - 1

(x + 1) (x^{2} - x - 1)

Schritte zur Lösung

x^{3} - 2 x - 1

Wende den rationalen Nullstellentest an

= (x + 1) \frac{x ^{3} - 2 x - 1}{x + 1}

\frac{x ^{3} - 2 x - 1}{x + 1} = x^{2} - x - 1

= (x + 1) (x^{2} - x - 1)

\frac{x + 32}{x + 6} \leq 3

n^{2} + n - 22526 = 0

∣ 5 x + 10 ∣ - 12 = 0

6 x^{2} - 18 x - 60 = 0

- 5 (x - 3) = - 25