What are the solutions to the equation n^2+n-22526=0 ?

The solutions to the equation n^2+n-22526=0 are n=(-1+sqrt(90105))/2 ,n=(-1-sqrt(90105))/2

Find the zeros of n^2+n-22526=0

The zeros of n^2+n-22526=0 are n=(-1+sqrt(90105))/2 ,n=(-1-sqrt(90105))/2

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n^{2} + n - 22526 = 0

n = \frac{- 1 + 90105}{2}, n = \frac{- 1 - 90105}{2}

Decimal Notation

n = 149.58747 \dots, n = - 150.58747 \dots

Solution steps

n^{2} + n - 22526 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 22526 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 22526) = 90105

n_{1, 2} = \frac{- 1 \pm 90105}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 1 + 90105}{2 \cdot 1}, n_{2} = \frac{- 1 - 90105}{2 \cdot 1}

n = \frac{- 1 + 90105}{2 \cdot 1} : \frac{- 1 + 90105}{2}

n = \frac{- 1 - 90105}{2 \cdot 1} : \frac{- 1 - 90105}{2}

The solutions to the quadratic equation are:

n = \frac{- 1 + 90105}{2}, n = \frac{- 1 - 90105}{2}

∣ 5 x + 10 ∣ - 12 = 0

6 x^{2} - 18 x - 60 = 0

- 5 (x - 3) = - 25

\frac{2 x + 3}{8} - \frac{2 x - 2}{9} \leq - 5

x^{2} + 8 x - 20 = 0

What are the solutions to the equation n^2+n-22526=0 ?
The solutions to the equation n^2+n-22526=0 are n=(-1+sqrt(90105))/2 ,n=(-1-sqrt(90105))/2
Find the zeros of n^2+n-22526=0
The zeros of n^2+n-22526=0 are n=(-1+sqrt(90105))/2 ,n=(-1-sqrt(90105))/2