What are the solutions to the equation 24+2x-x^2=0 ?

The solutions to the equation 24+2x-x^2=0 are x=-4,x=6

Find the zeros of 24+2x-x^2=0

The zeros of 24+2x-x^2=0 are x=-4,x=6

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24 + 2 x - x^{2} = 0

x = - 4, x = 6

Solution steps

24 + 2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 24}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 24 = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 ( - 1 )}, x_{2} = \frac{- 2 - 10}{2 ( - 1 )}

x = \frac{- 2 + 10}{2 ( - 1 )} : - 4

x = \frac{- 2 - 10}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 4, x = 6

3 x (x - 2) = 9 x^{2} - 11 x

593.7 x - 57 x^{2} = 1282.64 + 677.64

5 x^{2} \cdot x^{2}

10 y^{2} + 39 y + 14

5^{4}

What are the solutions to the equation 24+2x-x^2=0 ?
The solutions to the equation 24+2x-x^2=0 are x=-4,x=6
Find the zeros of 24+2x-x^2=0
The zeros of 24+2x-x^2=0 are x=-4,x=6