What is factor x^4+6x^3+7x^2-6x-8 ?

The solution to factor x^4+6x^3+7x^2-6x-8 is (x-1)(x+1)(x+2)(x+4)

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factor x^4+6x^3+7x^2-6x-8

factor

x^{4} + 6 x^{3} + 7 x^{2} - 6 x - 8

(x - 1) (x + 1) (x + 2) (x + 4)

Solution steps

x^{4} + 6 x^{3} + 7 x^{2} - 6 x - 8

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 6 x ^{3} + 7 x ^{2} - 6 x - 8}{x - 1}

\frac{x ^{4} + 6 x ^{3} + 7 x ^{2} - 6 x - 8}{x - 1} = x^{3} + 7 x^{2} + 14 x + 8

= (x - 1) (x^{3} + 7 x^{2} + 14 x + 8)

Factor

x^{3} + 7 x^{2} + 14 x + 8 : (x + 1) (x + 2) (x + 4)

= (x - 1) (x + 1) (x + 2) (x + 4)

\frac{- 80}{7 + 9}

\frac{k}{2} - 1 < 1

3 n^{2} + 16 n + 21

x (2 x + 1) (5 x - 30) \leq 0

\frac{3}{8} + 1

What is factor x^4+6x^3+7x^2-6x-8 ?
The solution to factor x^4+6x^3+7x^2-6x-8 is (x-1)(x+1)(x+2)(x+4)