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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3x^2+8x-4=0 ?
- The solutions to the equation 3x^2+8x-4=0 are x=(2(sqrt(7)-2))/3 ,x=-(2(2+sqrt(7)))/3
Find the zeros of 3x^2+8x-4=0
- The zeros of 3x^2+8x-4=0 are x=(2(sqrt(7)-2))/3 ,x=-(2(2+sqrt(7)))/3