What are the solutions to the equation 5x^2+5x+2=0 ?

The solutions to the equation 5x^2+5x+2=0 are x=-1/2+i(sqrt(15))/(10),x=-1/2-i(sqrt(15))/(10)

Find the zeros of 5x^2+5x+2=0

The zeros of 5x^2+5x+2=0 are x=-1/2+i(sqrt(15))/(10),x=-1/2-i(sqrt(15))/(10)

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5 x^{2} + 5 x + 2 = 0

x = - \frac{1}{2} + i \frac{15}{10}, x = - \frac{1}{2} - i \frac{15}{10}

Solution steps

5 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

Simplify

5^{2} - 4 \cdot 5 \cdot 2 : 15 i

x_{1, 2} = \frac{- 5 \pm 15 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 5 + 15 i}{2 \cdot 5}, x_{2} = \frac{- 5 - 15 i}{2 \cdot 5}

x = \frac{- 5 + 15 i}{2 \cdot 5} : - \frac{1}{2} + i \frac{15}{10}

x = \frac{- 5 - 15 i}{2 \cdot 5} : - \frac{1}{2} - i \frac{15}{10}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{15}{10}, x = - \frac{1}{2} - i \frac{15}{10}

\frac{a + 2}{16} - \frac{a + 3}{12} > \frac{a + 6}{24}

3 x^{2} - 14 x - 5

3^{\frac{1}{1}}

- 21 \leq \frac{2 x}{3} - \frac{1}{4} < 7

- 12 x < 60

What are the solutions to the equation 5x^2+5x+2=0 ?
The solutions to the equation 5x^2+5x+2=0 are x=-1/2+i(sqrt(15))/(10),x=-1/2-i(sqrt(15))/(10)
Find the zeros of 5x^2+5x+2=0
The zeros of 5x^2+5x+2=0 are x=-1/2+i(sqrt(15))/(10),x=-1/2-i(sqrt(15))/(10)