What is factor 100b^2+9c^2-60bc ?

The solution to factor 100b^2+9c^2-60bc is (10b-3c)^2

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factor 100b^2+9c^2-60bc

factor

100 b^{2} + 9 c^{2} - 60 b c

(10 b - 3 c)^{2}

Solution steps

100 b^{2} + 9 c^{2} - 60 b c

Group by common factors

= 100 b^{2} - 60 b c + 9 c^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

100 b^{2} = (10 b)^{2}

9 c^{2} = (3 c)^{2}

- 60 b c = - 2 \cdot 10 b \cdot 3 c

= (10 b)^{2} - 2 \cdot 10 b \cdot 3 c + (3 c)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(10 b)^{2} - 2 \cdot 10 b \cdot 3 c + (3 c)^{2} = (10 b - 3 c)^{2}

= (10 b - 3 c)^{2}

8 y - 3 (y - 2) > 2 y + 4 (2 y + 4)

40 x^{8} y + 64 x^{4} y

\frac{5 m}{5 m ^{4}}

x^{2} - 30 x - 64 = 0

lo g_{2} (9 x)

What is factor 100b^2+9c^2-60bc ?
The solution to factor 100b^2+9c^2-60bc is (10b-3c)^2