What is (x+2)(x-3)(x+8)<= 0 ?

The solution to (x+2)(x-3)(x+8)<= 0 is x<=-8\lor-2<= x<= 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+2)(x-3)(x+8)<= 0

(x + 2) (x - 3) (x + 8) \leq 0

x \leq - 8 or - 2 \leq x \leq 3

Interval Notation

(- \infty, - 8] \cup [- 2, 3]

Solution steps

(x + 2) (x - 3) (x + 8) \leq 0

Identify the intervals

x \leq - 8 or - 2 \leq x \leq 3

3 16 x^{4} y^{4} z

m^{2} - 4 m + 5 = 0

x^{2} - 14 x + 1 = 0

x (a + b) + 3 (a + b)

- \frac{5}{10}

What is (x+2)(x-3)(x+8)<= 0 ?
The solution to (x+2)(x-3)(x+8)<= 0 is x<=-8\lor-2<= x<= 3