What are the solutions to the equation x^2-14x+1=0 ?

The solutions to the equation x^2-14x+1=0 are x=7+4sqrt(3),x=7-4sqrt(3)

Find the zeros of x^2-14x+1=0

The zeros of x^2-14x+1=0 are x=7+4sqrt(3),x=7-4sqrt(3)

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x^{2} - 14 x + 1 = 0

x = 7 + 43, x = 7 - 43

Decimal Notation

x = 13.92820 \dots, x = 0.07179 \dots

Solution steps

x^{2} - 14 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 1 = 83

x_{1, 2} = \frac{- ( - 14 ) \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8 3}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8 3}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8 3}{2 \cdot 1} : 7 + 43

x = \frac{- ( - 14 ) - 8 3}{2 \cdot 1} : 7 - 43

The solutions to the quadratic equation are:

x = 7 + 43, x = 7 - 43

x (a + b) + 3 (a + b)

- \frac{5}{10}

\frac{1}{x} > - \frac{1}{2}

4 5^{- \frac{3}{2}} \cdot 4 5^{2}

x^{4} - 4 x^{3} + x^{2} - 4 x

What are the solutions to the equation x^2-14x+1=0 ?
The solutions to the equation x^2-14x+1=0 are x=7+4sqrt(3),x=7-4sqrt(3)
Find the zeros of x^2-14x+1=0
The zeros of x^2-14x+1=0 are x=7+4sqrt(3),x=7-4sqrt(3)