What are the solutions to the equation -4x^2+6x-1=0 ?

The solutions to the equation -4x^2+6x-1=0 are x=(3-sqrt(5))/4 ,x=(3+sqrt(5))/4

Find the zeros of -4x^2+6x-1=0

The zeros of -4x^2+6x-1=0 are x=(3-sqrt(5))/4 ,x=(3+sqrt(5))/4

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- 4 x^{2} + 6 x - 1 = 0

x = \frac{3 - 5}{4}, x = \frac{3 + 5}{4}

Decimal Notation

x = 0.19098 \dots, x = 1.30901 \dots

Solution steps

- 4 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) ( - 1 )}{2 ( - 4 )}

6^{2} - 4 (- 4) (- 1) = 25

x_{1, 2} = \frac{- 6 \pm 2 5}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 5}{2 ( - 4 )}, x_{2} = \frac{- 6 - 2 5}{2 ( - 4 )}

x = \frac{- 6 + 2 5}{2 ( - 4 )} : \frac{3 - 5}{4}

x = \frac{- 6 - 2 5}{2 ( - 4 )} : \frac{3 + 5}{4}

The solutions to the quadratic equation are:

x = \frac{3 - 5}{4}, x = \frac{3 + 5}{4}

- 3 (\frac{2}{5})^{0}

3 x^{2} - 8 x + 3 = 0

(7 + 3) (7 + 43)

7 - \frac{x}{7} = - 2

- 16 x^{2} + 3 x + 32 = 0

What are the solutions to the equation -4x^2+6x-1=0 ?
The solutions to the equation -4x^2+6x-1=0 are x=(3-sqrt(5))/4 ,x=(3+sqrt(5))/4
Find the zeros of -4x^2+6x-1=0
The zeros of -4x^2+6x-1=0 are x=(3-sqrt(5))/4 ,x=(3+sqrt(5))/4